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Lehrstuhl für Elektris he Antriebssysteme und Leistungselektronik
Te hnis he Universität Mün hen Prof. Dr.-Ing. RalphKennel
Ar isstraÿe 21
D80333 Mün hen
Email: ealei.tum.de
Internet: http://www.eal.ei.tum.de
Tel.: +49 (0)89 28928358
Fax: +49 (0)89 28928336
Power Ele troni s
Exer ise: Diode re tiers
2012
1
1 Theory
1.1 General remarks
1.1.1 Diode
In g. 1.1 the ir uit symbol and hara teristi s of an ideal, a real and a power diode are
shown. VS is the threshold voltage, the breakdown voltages is alled VR. In ontrast to onven-
tional diodes, power diodes have a ertain ohmi part whi h has to be onsidered if loss power
al ulations are made.
PSfrag repla ements
+−
pn
Cathode
Anode
I
V
VS
VR
ideal
real
Power diode
Blo king zone
Condu ting zone
Fig. 1.1: Cir uit symbol and hara teristi s of diodes
1.1.2 Average value
The average value of a signal orresponds to the arithmeti average value. For a periodi signal
v(t), e. g. a voltage, the average value an be al ulated as follows:
vM =1
T
t0+T∫
t0
v(t) dt (1.1)
1.1.3 Root mean square (RMS)
The root mean square of a signal is its quadrati mean value. A DC voltage with the same
value as the RMS of a periodi signal produ es exa tly the same thermal power on a resistor
(in average time).
The RMS of a periodi signal v(t) an be al ulated as follows:
Veff =
√
√
√
√
√
1
T
t0+T∫
t0
v2(t) dt (1.2)
For a sinusoidal signal with
v(t) = v sin (ωt)
it an be al ulated to
Veff =1
2
√2v (1.3)
2
1.2 Re tier ir uits
Re tier ir uits are ne essary for the onversion of AC voltages to DC voltages. In general the
ir uits an be divided into one-way ir uits and into two-way ir uits. Another dierentiation
an be made based on the number of ommutations per period. In the following hapters the
• one-way ir uits (M1, M2 and M3) and the
• two-way ir uits (B2 and B6)
are des ribed and explained.
1.2.1 Comparison of one-way ir uits and two-way ir uits
The two most important dieren es between one-way and two-way ir uits are:
1. One-way ir uits need less re tiers or diodes than bridge ir uits.
2. One-way ir uits need more omplex transformers.
In former times, when power semi ondu tors were not yet available, one-way ir uits were used
very often (mer ury vapor re tiers were very expensive). Today mostly two-way re tiers are
used.
3
1.3 M1 ir uit
1.3.1 Cir uit diagram
In g. 1.2 an M1 ir uit is shown.
PSfrag repla ements
V1 V2
Transformer
Vvil
vl
Fig. 1.2: M1 ir uit
1.3.2 Current and voltage traje tories
The ir uits shown in g. 1.3 (R load, RL load and RC load) were simulated with the program
PSIM
R©. The following values were used for the simulations:
V = 230V
f = 50Hz
R = 100Ω
C = 50µF
L = 50mH
The resulting traje tories of urrents and voltages are shown in g. 1.4.
V
A
V
A
V
A
Fig. 1.3: PSIM models of the M1 ir uit
The urrent iR(t) through the resistor R results from Ohm's law:
iR =vR
R
It is proportional to the voltage drop a ross the resistor.
The urrent owing through the apa itor C is given by the equation
iC = C · vC
4
0 0.01 0.02 0.03 0.04 0.05−200
0
200
400Voltages
Time [s]
Voltage [
V]
VRC
VR
VRL
0 0.01 0.02 0.03 0.04 0.05−5
0
5
10Currents
Time [s]
Curr
ent
[A]
IRC
IR
IRL
Fig. 1.4: Current and voltage traje tories (M1 ir uit)
A step in the urrent traje tory results be ause of the salient point in the voltage traje tory,
furthermore a urrent rise an be observed. At the beginning of a half wave the apa itor is
harged. If the peak of the half wave is ex eeded, both the apa itor and the voltage sour e
deliver urrent into the resistor R. The voltage sour e's voltage, however, goes down faster
than the apa itor's one (if the apa itor is dimensioned big enough). As soon as the apa itor
voltage is greater than the voltage of the voltage sour e, only the apa itor is delivering urrent
to the resistor. The diode urrent will stop owing and the diode is now in blo king mode. As
the apa itor is still not ompletely dis harged, it further delivers urrent to the resistor - either
until the omplete harge is drained over R or until the next half wave starts. A apa itor in
parallel to the resistor leads to a smoothing of the voltage.
The voltage a ross the indu tor L an be al ulated with the equation
vL = L · iL
the urrent iL owing through the indu tor then results to
iL =1
L
t0+T∫
t0
vL dt
From this results a PT1 traje tory or a smoothing of the urrent. This behavior results from
the fa t that in an indu tor a ux Ψ is reated. The ux always ountera ts against its ause
(the urrent through the indu tor). If the voltage of the sour e has be ome equal to zero,
magneti energy is still stored in the indu tor - the ux is still not zero. This leads to the fa t
that urrent is owing, even if the sour e voltage is already negative (Blo king ondition for
the diode: i = 0). The diode will blo k when the ux has be ome zero and when the urrent
through the diode has stopped owing.
5
1.3.3 Important parameters
For a sinusoidal input voltage
v(t) = v sin (ωt)
the diode's maximum blo king voltage is
Vvmax = v (1.4)
The ideal DC voltage, i. e. the average value of the re tied voltage, an be al ulated as follows:
Vdi =1
T
T∫
0
vL(t) dt =1
2π
π∫
0
v2 sin (ωt) dωt =v2
2π(− cos π + cos 0) =
v2
2π(1 + 1) =
v2
π
With
V2 =1
2
√2v2
follows:
Vdi =
√2
πV2 ≈ 0.4502V2 (1.5)
1.3.4 Transformer power rating
If the voltage for the one-way re tier is provided by a transformer, this part needs to have a
ertain power rating related to the DC part.
The transformer power rating an be al ulated a ording to the equation
PB =1
2
(
∑
i
VPiIPi +∑
i
VSiISi
)
(1.6)
The transformer power rating is the arithmeti average value of the sum of the apparent powers
on the primary and on the se ondary side. For urrents and voltages RMS values have to be
used in equation 1.6.
The power in the DC part is
Pd = VdiId (1.7)
1.3.4.1 Pure R load
The ratio between the transformer power rating and the power in the DC part results to
PB
Pd
≈ 3.09 (1.8)
A derivation shall be omitted at this point. The transformer power rating has to be more than
three times greater than the power in the DC part if a pure resistive load is onsidered!
6
1.4 M2 ir uit
The M2 ir uit uses a transformer with entral tapping.
1.4.1 Cir uit diagram
In g. 1.5 an M2 ir uit is drawn.
PSfrag repla ements
V1
VS1
VS2
Transformer
D1
D2
ilvl
Fig. 1.5: M2 ir uit
1.4.2 General fun tional prin iple
The ir uit shown in g. 1.6 was rst simulated with PSIM
R©with a pure resistive load in order
to show the general fun tional prin iple. Again the values given in hapter 1.3.2 were used. It
has to be noted that here for ea h one of the voltage sour es only
V = 115VRMS
were used. This orresponds to a transformer with entral tapping and a tranformation ratio of
1. In g. 1.7 the transformer voltages, the voltage drop a ross the resistor, the urrents through
A
A
V
V
A V
Fig. 1.6: PSIM model for showing the general fun tional prin iple of the M2 ir uit
both diodes and the urrent through the resistor are shown. As it an be seen, the upper diode
(D1) is ondu ting during the positive half wave, the lower one (D2) during a negative half
wave, i. e. always the diode whi h has a positive potential.
1.4.3 Current and voltage traje tories for R-, RC- and RL load
A further simulation was made using PSIM
R©in order to plot the urrent and voltage traje tories
for a pure R load, an RC load and an RL load. The traje tories an be explained analogously to
hapter 1.3.2. The simulation models are shown in g. 1.8, the urrent and voltage traje tories
in g. 1.9. In ontrast to the M1 ir uit here already a smaller apa itor C is su ient in order
to smooth the load voltage be ause two half waves per period are used.
7
0 0.005 0.01 0.015 0.02 0.025−200
0
200Transformer voltages
Time [s]
Vo
lta
ge
[V
]
Voben
Vunten
0 0.005 0.01 0.015 0.02 0.0250
100
200Voltage drop on R
Time [s]
Vo
lta
ge
[V
]
0 0.005 0.01 0.015 0.02 0.025−2
0
2Current in upper branch
Time [s]
Cu
rre
nt [A
]
0 0.005 0.01 0.015 0.02 0.025−2
0
2Current in lower branch
Time [s]
Curr
ent
[A]
0 0.005 0.01 0.015 0.02 0.0250
1
2Current through R
Time [s]
Curr
ent
[A]
Fig. 1.7: Current and voltage traje tories showing the general fun tional prin iple of the M2
ir uit
A A AV V V
Fig. 1.8: PSIM models of the M2 ir uit with dierent loads
8
0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04 0.045 0.05−50
0
50
100
150
200Voltages
Time [s]
Vo
lta
ge
[V
]
VR
VRL
VRC
0 0.005 0.01 0.015 0.02 0.025 0.03 0.035 0.04 0.045 0.05−1
0
1
2
3
4
5
6Currents
Time [s]
Cu
rre
nt [A
]
IR
IRL
IRC
Fig. 1.9: Current and voltage traje tories (M2 ir uit)
1.4.4 Important parameters
For a sinusoidal input voltage the diode's maximum blo king voltage is
Vvmax = 2vSi (1.9)
The ideal DC voltage is
Vdi =2√2
πVSi ≈ 0.901VSi (1.10)
Important: The voltage loss resulting from ommutation ee ts has to be subtra ted from this
voltage!
1.4.5 Transformer power rating
1.4.5.1 Pure R load
For a pure R load the ratio between transformer power rating and power in the DC part is
ST
Pd
≈ 1.48 (1.11)
A derivation shall be omitted at this point.
1.4.5.2 RL load with L → ∞
The transformer apparent power results to
ST ≈ 1.34Pd (1.12)
9
1.5 B2 ir uit
Nowadays the B2 ir uit is mostly used in power supplies for the re ti ation of single phase
AC voltages.
1.5.1 Cir uit diagram
In g. 1.10 a B2 ir uit is drawn.
PSfrag repla ements
V1 V2vL
iL
D1
D2
D3 D4
Fig. 1.10: B2 ir uit
1.5.2 General fun tional prin iple
The ir uit shown in g. 1.11 was simulated as well, in this ase espe ially in order to show
the general fun tional prin iple. The values given in hapter 1.3.2 were also used for these
simulations. In g. 1.12 the urrent and voltage traje tories are shown. During a positive half
wave the urrent is owing through the diodes D1 and D4, during a negative half wave through
D2 and D3, as these do then have positive potential. In this ase both half waves are used.
A
V
A
A
A
A
Fig. 1.11: PSIM model showing the general fun tional prin iple of the B2 ir uit
1.5.3 Current and voltage traje tories for R, RC and RL load
Another simulation was arried out in order to plot the urrent and voltage traje tories for a
pure R load, an RC load and an RL load. The traje tories an be explained analogously to
10
0 0.005 0.01 0.015 0.02 0.0250
200
400Voltage drop on R
Vo
lta
ge
[V
]
Time [s]
0 0.005 0.01 0.015 0.02 0.025−5
0
5Current through upper left diode
Cu
rre
nt
[A]
Time [s]
0 0.005 0.01 0.015 0.02 0.025−5
0
5Current through lower right diode
Curr
en
t [A
]
Time [s]
0 0.005 0.01 0.015 0.02 0.025−5
0
5Current through upper right diode
Curr
ent
[A]
Time [s]
0 0.005 0.01 0.015 0.02 0.025−5
0
5Current through lower left diode
Curr
ent
[A]
Time [s]
0 0.005 0.01 0.015 0.02 0.0250
2
4Current through R
Curr
ent [A
]
Time [s]
Fig. 1.12: Current and voltage traje tories showing the general fun tional prin iple of the B2
ir uit
11
hapter 1.3.2. The models are shown in g. 1.13, the urrent and voltage traje tories in g. 1.14.
It has to be noted that in this ase, analogously to the M2 ir uit, already a smaller apa itor
C is su ient in order to smooth the load voltage be ause here also two half waves are used
per period.
A
V
A
V
A
V
Fig. 1.13: PSIM models of the B2 ir uit with dierent loads
0 0.005 0.01 0.015 0.02 0.025−100
0
100
200
300
400Voltages
Voltage [V
]
Time [s]
VR
VRL
VRC
0 0.005 0.01 0.015 0.02 0.025−2
0
2
4
6
8Currents
Curr
ent [A
]
Time [s]
IR
IRL
IRC
Fig. 1.14: Current and voltage traje tories (B2 ir uit)
1.5.4 Important parameters
The ideal DC voltage is
Vdi =2√2
πVS ≈ 0.901VS (1.13)
The diode's maximum blo king voltage is
Vvmax = vS (1.14)
12
1.5.5 Transformer power rating
1.5.5.1 Pure R load
The transformer apparent power results to
ST =≈ 1.23Pd (1.15)
1.5.5.2 RL load with L → ∞
In this ase the transformer apparent power results to
SS ≈ 1.11Pd (1.16)
1.5.5.3 RC load with C → ∞
The transformer apparent power an be al ulated to
S = 1.21 (Vdi + 2VS) Id (1.17)
A derivation shall be omitted at this point.
13
1.6 Three-phase ir uits
The following ir uits are used for the re ti ation of three-phase alternating urrents.
1.6.1 M3 ir uit
1.6.1.1 Cir uit diagram
In g. 1.15 an M3 ir uit is drawn, the transformer is onne ted on both sides via a star
onne tion.
PSfrag repla ements
3 ∼
vL
iL
D1
D2
D3
Fig. 1.15: M3 ir uit
1.6.1.2 General fun tional prin iple
The ir uit shown in g. 1.16 was also simulated, in this ase espe ially in order to show the
general fun tional prin iple. The values given in hapter 1.3.2 were used, in this ase, however,
a three-phase voltage sour e with VS = 230V. In g. 1.17 the urrent and voltage traje tories
are shown. It an be seen that only the diode with positive potential is ondu ting. This means
that, if, e. g., V1 is the highest voltage, D1 is ondu ting, if V2 is the highest one, then D2 is
ondu ting. The same is valid for U3 and D3.
1.6.1.3 Current and voltage traje tories for R, RC and RL loads
A further simulation was arried out in order to plot the urrent and voltage traje tories for
a pure R, an RC and an RL load. The traje tories an be explained analogously to hapter
1.3.2. The models are shown in g. 1.18, the urrent and voltage traje tories in g. 1.19.
A
A
A
A
V
Fig. 1.16: PSIM model for showing the general fun tional prin iple of the M3 ir uit
14
0 0.005 0.01 0.015 0.02 0.025−500
0
500Transformer voltages
Time [s]
Vo
lta
ge
[V
]
V1
V2
V3
0 0.005 0.01 0.015 0.02 0.0250
200
400Voltage drop on R
Time [s]
Vo
lta
ge
[V
]
0 0.005 0.01 0.015 0.02 0.025−2
0
2
4Current through branch 1
Time [s]
Curr
ent
[A]
0 0.005 0.01 0.015 0.02 0.025−2
0
2
4Current throuhg branch 2
Time [s]
Curr
ent
[A]
0 0.005 0.01 0.015 0.02 0.025−2
0
2
4Current through branch 3
Time [s]
Curr
ent
[A]
0 0.005 0.01 0.015 0.02 0.0250
2
4Current through R
Time [s]
Curr
ent
[A]
Fig. 1.17: Current and voltage traje tories for showing the general fun tional prin iple of the
M3 ir uit
15
A
V
A
V
A
V
Fig. 1.18: PSIM models of the M3 ir uit with dierent loads
1.6.1.4 Important parameters
As it has already been shown in hapter 1.6.1.2, always only one diode is ondu ting, while
the other two ones are blo king. Hen e, the blo king diodes are stressed with the line to line
voltage of the se ondary transformer side.
In a three-phase system the line to line voltages (mesh voltages) an be al ulated from the
line to neutral voltages as follows:
VV =√3VS (1.18)
The following an be obtained for the maximum blo king voltage of the diodes:
Vvmax =√2VV =
√2√3VS =
√6VS ≈ 2.45VS (1.19)
For the al ulation of the ideal DC voltage it is better to integrate only over a third of the period,
2π3. In this ase the integration is done for the voltage V1. The lower integration boundary is
obtained from the interse tion of V1 with V2, the upper one from the interse tion of V1 with V3.
The boundaries an be obtained if the equations for the voltages are set equal to ea h other.
In g. 1.20 the voltages are shown. Hen e, the ideal DC voltage an be al ulated to
Vdi =3
2π
5
6π∫
π
6
√2VS sin (ωt) dωt =
3
2π
√2VS [− cos (ωt)]
5
6π
π
6
= . . . =3√6
2πVS ≈ 1.17VS (1.20)
If, instead of this, the line to line voltage is used,
Vdi =3√2
2πVV ≈ 0.68VV (1.21)
an be obtained.
16
0 0.005 0.01 0.015 0.02 0.0250
50
100
150
200
250
300
350Voltages
Time [s]
Voltage [V
]
VR
VRL
VRC
0 0.005 0.01 0.015 0.02 0.025−2
0
2
4
6
8
Time [s]
Curr
ent [A
]
Currents
IR
IRL
IRC
Fig. 1.19: Current and voltage traje tories (M3 ir uit)
0 0.5 1 1.5 2−400
−300
−200
−100
0
100
200
300
400
ω t / π
Voltage [V
]
V1
V2
V3
Fig. 1.20: Voltages in three-phase systems
17
1.6.2 B6 ir uit
Nowadays the B6 ir uit is mostly used for the re ti ation of three-phase AC voltages.
1.6.2.1 Cir uit diagram
In g. 1.21 a B6 ir uit is drawn.
PSfrag repla ements
3 ∼ vL
iL
D1 D2 D3
D4 D5 D6
Fig. 1.21: B6 ir uit
1.6.2.2 General fun tional prin iple
The ir uit shown in g. 1.22 was also simulated, in this ase espe ially in order to show the
general fun tional prin iple. The values given in hapter 1.3.2 were used as well. In g. 1.23
the urrent and voltage traje tories are shown. From the upper diodes (D1, D2 and D3) the
one with the highest potential is ondu ting, from the lower diodes (D4, D5 and D6) the one
whose phase urrently has the most negative potential.
A
V
V
V
V
AAA
A A A
Fig. 1.22: PSIM model for showing the general fun tional prin iple of the B6 ir uit
18
0 0.005 0.01 0.015 0.02 0.025−500
0
500Transformer voltages
Time [s]
Voltage [V
]
V1
V2
V3
0 0.005 0.01 0.015 0.02 0.0250
200
Voltage drop on R
Time [s]
Voltage [V
]
0 0.005 0.01 0.015 0.02 0.025−10
0
10Current through upper left diode
Time [s]
Curr
ent [A
]
0 0.005 0.01 0.015 0.02 0.025−10
0
10Current through upper middle diode
Time [s]
Curr
ent [A
]
0 0.005 0.01 0.015 0.02 0.025−10
0
10Current through upper right diode
Time [s]
Curr
ent [A
]
0 0.005 0.01 0.015 0.02 0.025−10
0
10Current through lower left diode
Time [s]
Curr
ent [A
]
0 0.005 0.01 0.015 0.02 0.025−10
0
10Current through lower middle diode
Time [s]
Curr
ent [A
]
0 0.005 0.01 0.015 0.02 0.025−10
0
10Current through lower right diode
Time [s]
Curr
ent [A
]
0 0.005 0.01 0.015 0.02 0.0250
5
Current through R
Time [s]
Curr
ent [A
]
Fig. 1.23: Current and voltage traje tories showing the general fun tional prin iple of the B6
ir uit
19
1.6.2.3 Current and voltage traje tories for R, RC and RL load
A further simulation was made in order to plot the urrent and voltage traje tories for a pure
R, an RC and an RL load. The traje tories an be explained analogously to hapter 1.3.2. The
models are shown in g. 1.24, the urrent and voltage traje tories in g. 1.25. In order to make
the voltage smoothing visible, in this ase a apa itor with C = 500µF was sele ted.
A
VV
A
V
A
Fig. 1.24: PSIM models of the B6 ir uit with dierent loads
1.6.2.4 Important parameters
The B6 ir uit an be interpreted as a series onne tion of two M3 ir uits. Hen e, the ideal
DC voltage is twi e the one of the M3 ir uit:
Vdi = 2 ·3
2π
√6VS =
3√6
πVS ≈ 2.34VS (1.22)
Related to the line to line voltage VV the following relation an be obtained:
Vdi =3√2
πVV ≈ 1.35VV (1.23)
the diode's maximum blo king voltage is (without derivation for sake of brevity)
VVmax = 1.05Vdi (1.24)
The B6 ir uit is quite often also used in industrial abinets to provide a 24V DC voltage: First
the voltage is transformed via a three-phase transformer to VV = 18V (line to line voltage),
the ideal DC voltage then results to a. 24V a ording to equation 1.23. If the spe i ation
for the voltage ripple is sele ted well, no smoothing apa itor is ne essary. This makes su h a
setup very robust against power u tuations.
20
0 0.005 0.01 0.015 0.02 0.025150
200
250
300
350Voltages
Voltage [V
]
Time [s]
VR
VRL
VRC
0 0.005 0.01 0.015 0.02 0.0250
2
4
6Currents
Curr
ent [A
]
Time [s]
IR
IRL
0 0.005 0.01 0.015 0.02 0.025−50
0
50
100
150Current through RC element
Curr
ent [A
]
Time [s]
Fig. 1.25: Current and voltage traje tories (B6 ir uit)
21