Serie de Fourier v2

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  • 8/18/2019 Serie de Fourier v2

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    L(+( ") %&3$0$& %$,.+"2&

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    "02&0.", ,$ + 6 )

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    Dado que es una función compleja y su conjugado:

    Z = a+jb + a-jb = 2a

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  • 8/18/2019 Serie de Fourier v2

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