Practica de Fisica No. 3 5im11

8/19/2019 Practica de Fisica No. 3 5im11

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INSTITUTO POLITECNICO NACIONALCENTRO DE ESTUDIOS CIENTIFICOS Y TECNOLOGICOS

“LAZARO CARDENAS”

NOMBRE: CASTILLO ZENIL OMARALBERTONo. DE BOL.: 2013041663

TURNO: MATUTINO No. DE EUIPO: 6 GRUPO: !IM11

CALIFICACION: """"""""""""""""""

PRACTICA No.3

I. NOMBRE DE LA PRÁCTICA.LEY DE COULOMB

II. JUSTIFICACION.L# $%& '% (o)$o*+ %, +-,(# %/ %$%(o,-(# o)% %$$# % $#, #((o/%, *))#,%/% (##, %$5((#,. E/o/(%, %, *o#/% %/ %,# -((# %7%()# )/#(o*o+#(8/ ()#$#9# & ()#/#9# '% %,# $%&

III. OBJETIVOS.# Co*o+# )% $# 7)%;# '% ##((8/ o '% %)$,8/ %/% 'o, ()%o,

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IV. PRERREQUISITOS.P## %$ +)%/ '%,#o$$o '% %,# -((# ,% %)%% )% %$ #$)*/o %/# $o,(o/o(*%/o, ,)%/%,:

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VII. DESARROLLO DE LA PRÁCTICA 0 CUESTIONARIO.

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3.JE/)/(# $# $%& '% Co)$o*+

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EQERCICIOS DE PRCTICA:

T

Ѳ F%

#/ Ѳ2 &240 (*

F TF%F& T ,%/ Ѳ 0

F T (o, Ѳ F%S%/ Ѳ F% T#/ Ѳ F%

2H.4S%/ Ѳ0.421 T#/ Ѳ0.!63

Fe= wtanѲ

Fe= 29.4

(1.001 )=29.37

Fe=29.4

(1.00025 )=29.39

Fe= 29.4

(1.00075 )=29.37

Fe= 29.4

(1.000025 )=29.39

Y1 √ 402−−2

1

2

40.04

Y2 √ 402−−1

2

2

40.01

Y3 √ 402−−0.5

3

2

40.003

Y4 √ 402−−0.4

4

2

40.001

T#/ Ѳ &1 40 (*1.001 T#/ Ѳ2 &240 (*1.0002! T#/ Ѳ3 &340 (*1.000>! T#/ Ѳ4 &440 (*1.00002!

J1 &140(* 4!.02 J1 &240(* 4!.00> J1 &340(* 4!.02

J1 &440(* 4!.000>

F =k q1q2

r2

k q1

r2 = F

√ Fr

k

r

2=q2

√ 29.37

9 x109 NM /C

10cm=3.26 X 1010

F =9 x109 NM /C

3.26 x1010

−2=−1.46 x10

20

F =9 x109 NM /C

3.26 x1010

−1=−2.93 x 10

20


7/10

G#(#:

F

2.H3

2.?0

1.46

1.33

R

0.16 0.2! 1 4


8/10

“” DE GOIN:


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Practica de Fisica No. 3 5im11